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Preview big-operator task symbols with their argument inside #299

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Preview big-operator task symbols with their argument inside #299

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42 changes: 42 additions & 0 deletions app/tests/symbolic_preview_test.py
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Original file line number Diff line number Diff line change
Expand Up @@ -362,3 +362,45 @@ def test_curly_brace_multiple_answers_still_works(self, strict_syntax):
result = preview_function("{1, 2}", params)
assert result["preview"]["latex"] == "\\left\\{1,~2\\right\\}"
assert result["preview"]["sympy"] == "{1, 2}"

@pytest.mark.parametrize(
"response, latex, sympy", [
# summation() with explicit bounds, rendered by SymPy
(
"summation((4/n**2)(-1)**n cos(nx), (n, 1, oo))",
r"\sum_{n=1}^{\infty} \frac{4 \cdot \left(-1\right)^{n} \cdot \cos{\left(n \cdot x \right)}}{n^{2}}",
"summation((4/n**2)(-1)**n cos(nx), (n, 1, oo))",
),
# infsum is a task symbol written as a big operator: its argument goes inside the sum
(
"infsum((-1)^n / n^2)",
r"\sum_{n=1}^{\infty} \frac{\left(-1\right)^{n}}{n^{2}}",
"infsum((-1)^n / n^2)",
),
(
"infsum((4/n^2)*(-1)^n*cos(nx))",
r"\sum_{n=1}^{\infty} \frac{4 \cdot \left(-1\right)^{n} \cdot \cos{\left(n \cdot x \right)}}{n^{2}}",
"infsum((4/n^2)*(-1)^n* cos(nx))",
),
(
"((pi^2)/(3))+infsum((4/n^2)*(-1)^n*cos(nx))",
r"\frac{\pi^{2}}{3} + \sum_{n=1}^{\infty} \frac{4 \cdot \left(-1\right)^{n} \cdot \cos{\left(n \cdot x \right)}}{n^{2}}",
"(( pi^2)/(3))+infsum((4/n^2)*(-1)^n* cos(nx))",
),
]
)
def test_sum_preview(self, response, latex, sympy):
# From #261: infsum((-1)^n/n^2) was the product infsum*(...), so the sum was printed inside the fraction.
params = {
"is_latex": False,
"strict_syntax": False,
"elementary_functions": True,
"symbols": {
"infsum": {"aliases": [], "latex": "\\sum_{n=1}^{\\infty}"},
"pi": {"aliases": [], "latex": "\\pi"},
},
}

result = preview_function(response, params)
assert result["preview"]["latex"] == latex
assert result["preview"]["sympy"] == sympy
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